Optimal. Leaf size=111 \[ -\frac{2 (a+b x)^{3/2} (B d-A e)}{3 e (d+e x)^{3/2} (b d-a e)}-\frac{2 B \sqrt{a+b x}}{e^2 \sqrt{d+e x}}+\frac{2 \sqrt{b} B \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{a+b x}}{\sqrt{b} \sqrt{d+e x}}\right )}{e^{5/2}} \]
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Rubi [A] time = 0.0603796, antiderivative size = 111, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.208, Rules used = {78, 47, 63, 217, 206} \[ -\frac{2 (a+b x)^{3/2} (B d-A e)}{3 e (d+e x)^{3/2} (b d-a e)}-\frac{2 B \sqrt{a+b x}}{e^2 \sqrt{d+e x}}+\frac{2 \sqrt{b} B \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{a+b x}}{\sqrt{b} \sqrt{d+e x}}\right )}{e^{5/2}} \]
Antiderivative was successfully verified.
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Rule 78
Rule 47
Rule 63
Rule 217
Rule 206
Rubi steps
\begin{align*} \int \frac{\sqrt{a+b x} (A+B x)}{(d+e x)^{5/2}} \, dx &=-\frac{2 (B d-A e) (a+b x)^{3/2}}{3 e (b d-a e) (d+e x)^{3/2}}+\frac{B \int \frac{\sqrt{a+b x}}{(d+e x)^{3/2}} \, dx}{e}\\ &=-\frac{2 (B d-A e) (a+b x)^{3/2}}{3 e (b d-a e) (d+e x)^{3/2}}-\frac{2 B \sqrt{a+b x}}{e^2 \sqrt{d+e x}}+\frac{(b B) \int \frac{1}{\sqrt{a+b x} \sqrt{d+e x}} \, dx}{e^2}\\ &=-\frac{2 (B d-A e) (a+b x)^{3/2}}{3 e (b d-a e) (d+e x)^{3/2}}-\frac{2 B \sqrt{a+b x}}{e^2 \sqrt{d+e x}}+\frac{(2 B) \operatorname{Subst}\left (\int \frac{1}{\sqrt{d-\frac{a e}{b}+\frac{e x^2}{b}}} \, dx,x,\sqrt{a+b x}\right )}{e^2}\\ &=-\frac{2 (B d-A e) (a+b x)^{3/2}}{3 e (b d-a e) (d+e x)^{3/2}}-\frac{2 B \sqrt{a+b x}}{e^2 \sqrt{d+e x}}+\frac{(2 B) \operatorname{Subst}\left (\int \frac{1}{1-\frac{e x^2}{b}} \, dx,x,\frac{\sqrt{a+b x}}{\sqrt{d+e x}}\right )}{e^2}\\ &=-\frac{2 (B d-A e) (a+b x)^{3/2}}{3 e (b d-a e) (d+e x)^{3/2}}-\frac{2 B \sqrt{a+b x}}{e^2 \sqrt{d+e x}}+\frac{2 \sqrt{b} B \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{a+b x}}{\sqrt{b} \sqrt{d+e x}}\right )}{e^{5/2}}\\ \end{align*}
Mathematica [A] time = 0.844735, size = 148, normalized size = 1.33 \[ \frac{2 \left (\frac{\sqrt{e} \sqrt{a+b x} \left (a e (A e+2 B d+3 B e x)+A b e^2 x-b B d (3 d+4 e x)\right )}{b d-a e}+\frac{3 B (b d-a e)^{3/2} \left (\frac{b (d+e x)}{b d-a e}\right )^{3/2} \sinh ^{-1}\left (\frac{\sqrt{e} \sqrt{a+b x}}{\sqrt{b d-a e}}\right )}{b}\right )}{3 e^{5/2} (d+e x)^{3/2}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.023, size = 503, normalized size = 4.5 \begin{align*} -{\frac{1}{ \left ( 3\,ae-3\,bd \right ){e}^{2}} \left ( -3\,B\ln \left ( 1/2\,{\frac{2\,bxe+2\,\sqrt{ \left ( bx+a \right ) \left ( ex+d \right ) }\sqrt{be}+ae+bd}{\sqrt{be}}} \right ){x}^{2}ab{e}^{3}+3\,B\ln \left ( 1/2\,{\frac{2\,bxe+2\,\sqrt{ \left ( bx+a \right ) \left ( ex+d \right ) }\sqrt{be}+ae+bd}{\sqrt{be}}} \right ){x}^{2}{b}^{2}d{e}^{2}-6\,B\ln \left ( 1/2\,{\frac{2\,bxe+2\,\sqrt{ \left ( bx+a \right ) \left ( ex+d \right ) }\sqrt{be}+ae+bd}{\sqrt{be}}} \right ) xabd{e}^{2}+6\,B\ln \left ( 1/2\,{\frac{2\,bxe+2\,\sqrt{ \left ( bx+a \right ) \left ( ex+d \right ) }\sqrt{be}+ae+bd}{\sqrt{be}}} \right ) x{b}^{2}{d}^{2}e+2\,Axb{e}^{2}\sqrt{ \left ( bx+a \right ) \left ( ex+d \right ) }\sqrt{be}-3\,B\ln \left ( 1/2\,{\frac{2\,bxe+2\,\sqrt{ \left ( bx+a \right ) \left ( ex+d \right ) }\sqrt{be}+ae+bd}{\sqrt{be}}} \right ) ab{d}^{2}e+3\,B\ln \left ( 1/2\,{\frac{2\,bxe+2\,\sqrt{ \left ( bx+a \right ) \left ( ex+d \right ) }\sqrt{be}+ae+bd}{\sqrt{be}}} \right ){b}^{2}{d}^{3}+6\,Bxa{e}^{2}\sqrt{ \left ( bx+a \right ) \left ( ex+d \right ) }\sqrt{be}-8\,Bxbde\sqrt{ \left ( bx+a \right ) \left ( ex+d \right ) }\sqrt{be}+2\,Aa{e}^{2}\sqrt{ \left ( bx+a \right ) \left ( ex+d \right ) }\sqrt{be}+4\,Bade\sqrt{ \left ( bx+a \right ) \left ( ex+d \right ) }\sqrt{be}-6\,Bb{d}^{2}\sqrt{ \left ( bx+a \right ) \left ( ex+d \right ) }\sqrt{be} \right ) \sqrt{bx+a}{\frac{1}{\sqrt{ \left ( bx+a \right ) \left ( ex+d \right ) }}}{\frac{1}{\sqrt{be}}} \left ( ex+d \right ) ^{-{\frac{3}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 6.41407, size = 1107, normalized size = 9.97 \begin{align*} \left [\frac{3 \,{\left (B b d^{3} - B a d^{2} e +{\left (B b d e^{2} - B a e^{3}\right )} x^{2} + 2 \,{\left (B b d^{2} e - B a d e^{2}\right )} x\right )} \sqrt{\frac{b}{e}} \log \left (8 \, b^{2} e^{2} x^{2} + b^{2} d^{2} + 6 \, a b d e + a^{2} e^{2} + 4 \,{\left (2 \, b e^{2} x + b d e + a e^{2}\right )} \sqrt{b x + a} \sqrt{e x + d} \sqrt{\frac{b}{e}} + 8 \,{\left (b^{2} d e + a b e^{2}\right )} x\right ) - 4 \,{\left (3 \, B b d^{2} - 2 \, B a d e - A a e^{2} +{\left (4 \, B b d e -{\left (3 \, B a + A b\right )} e^{2}\right )} x\right )} \sqrt{b x + a} \sqrt{e x + d}}{6 \,{\left (b d^{3} e^{2} - a d^{2} e^{3} +{\left (b d e^{4} - a e^{5}\right )} x^{2} + 2 \,{\left (b d^{2} e^{3} - a d e^{4}\right )} x\right )}}, -\frac{3 \,{\left (B b d^{3} - B a d^{2} e +{\left (B b d e^{2} - B a e^{3}\right )} x^{2} + 2 \,{\left (B b d^{2} e - B a d e^{2}\right )} x\right )} \sqrt{-\frac{b}{e}} \arctan \left (\frac{{\left (2 \, b e x + b d + a e\right )} \sqrt{b x + a} \sqrt{e x + d} \sqrt{-\frac{b}{e}}}{2 \,{\left (b^{2} e x^{2} + a b d +{\left (b^{2} d + a b e\right )} x\right )}}\right ) + 2 \,{\left (3 \, B b d^{2} - 2 \, B a d e - A a e^{2} +{\left (4 \, B b d e -{\left (3 \, B a + A b\right )} e^{2}\right )} x\right )} \sqrt{b x + a} \sqrt{e x + d}}{3 \,{\left (b d^{3} e^{2} - a d^{2} e^{3} +{\left (b d e^{4} - a e^{5}\right )} x^{2} + 2 \,{\left (b d^{2} e^{3} - a d e^{4}\right )} x\right )}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (A + B x\right ) \sqrt{a + b x}}{\left (d + e x\right )^{\frac{5}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.80507, size = 324, normalized size = 2.92 \begin{align*} \frac{B \sqrt{b}{\left | b \right |} e^{\frac{1}{2}} \log \left ({\left | -\sqrt{b x + a} \sqrt{b} e^{\frac{1}{2}} + \sqrt{b^{2} d +{\left (b x + a\right )} b e - a b e} \right |}\right )}{16 \,{\left (b^{6} d e^{4} - a b^{5} e^{5}\right )}} + \frac{\sqrt{b x + a}{\left (\frac{{\left (4 \, B b^{4} d{\left | b \right |} e^{2} - 3 \, B a b^{3}{\left | b \right |} e^{3} - A b^{4}{\left | b \right |} e^{3}\right )}{\left (b x + a\right )}}{b^{8} d^{2} e^{4} - 2 \, a b^{7} d e^{5} + a^{2} b^{6} e^{6}} + \frac{3 \,{\left (B b^{5} d^{2}{\left | b \right |} e - 2 \, B a b^{4} d{\left | b \right |} e^{2} + B a^{2} b^{3}{\left | b \right |} e^{3}\right )}}{b^{8} d^{2} e^{4} - 2 \, a b^{7} d e^{5} + a^{2} b^{6} e^{6}}\right )}}{48 \,{\left (b^{2} d +{\left (b x + a\right )} b e - a b e\right )}^{\frac{3}{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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